Question

A quartz vessel contains dry air with pressure 750 mm of Hg at 251 K. The vessel can with stand up to a pressure of 1150 mm of Hg. The temperature without breaking the vessel. (Pressure coefficient of air is0.00366/°C (or) 1/273/°C )

Answer 1

$\sf{\huge{\boxed{\purple{Correct\: Question? }}}}$

• Refers to the attachment; {Source Provided by the asker }

$\huge\bf\pink{\mid{\overline{\underline{Given :- }}}\mid}$

• A quartz vessel contains dry air with pressure 750 mm of Hg at 251 K.

• The vessel can with stand up to a pressure of 1150 mm of Hg.

• Pressure coefficient of air is0.00366/°C

$\huge\bf\orange{\mid{\overline{\underline{To\:Find :- }}}\mid}$

• The temperature without breaking the vessel.

$\huge\bf\red{\mid{\overline{\underline{Answer :- }}}\mid}$

According to the question,

A quartz vessel contains dry air with pressure 750 mm of Hg at 251 K.

Here , we have to use the unitary method.

750 mm of Hg ➝ 251 K

1 mm of Hg = 251/750

The vessel can with stand up to a pressure of 1150 mm of Hg.

So, For 1150 mm of Hg

➝ 1150 × 251/750

➝ 1.5 × 251

➝ 384 K

We know that converting,

K to C

°C = (K - 273)

384 K

➝ (384 - 273)

➝ 111°C

Hence, Option.C) 111°C is the temperature without breaking the vessel.

Answer 2

Question :

A quartz vessel contains dry air with pressure 750 mm of Hg at 251 K. The vessel can with stand up to a pressure of 1150 mm of Hg. The temperature without breaking the vessel. (Pressure coefficient of air is0.00366/°C (or) 1/273/°C )

Given :

• A quartz vessel contains dry air with pressure 750 mm of Hg at 251 K.

• The vessel can with stand up to a pressure of 1150 mm of Hg.

To find :

• The temperature without breaking the vessel. (Pressure coefficient of air is0.00366/°C (or) 1/273/°C )

Concept :

• Temperature is an objective measurement of how hot or cold an object is.

• It can be measured with a thermometer or a calorimeter.

• It is a means of determining the internal energy contained within a given system

Let's start :

$\: \: \: \: \: \: \: \: \: \: \rightarrow \sf750 \: mm \: of \: Hg = 251 k$

$\: \: \: \: \: \: \: \: \: \: \: \rightarrow\sf1 \: mm \: of \: Hg = \frac{251}{750}$

• So, for 1150 mm of Hg

$\: \: \: \: \: \: \: \: \: \: \: \: \rightarrow \sf1150 \times \frac{251}{750}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \rightarrow \sf1.5 \times 251$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \rightarrow \sf348k$

Now Converting K to C

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \rightarrow \sf℃ = ( K - 273 )$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \rightarrow \sf38k$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \rightarrow \sf(384 - 273)$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: { \underline {\underline{ \pink{\sf111 \degree \: c}}}}$

So your answer is done mate :)