Question

A quedratic polynomial the sum of whose zeroes is 0 and one zeroes is 3 is.​

Answer 1

Answer:

$one \: zero \: is \: 3 \\ sum \: = 0 \\ \alpha + 3 = 0 \\ \alpha = 0 - 3 = - 3$

other root is -3

sum of the zeros = 3 - 3= 0

product of the zeros = 3(-3) = -9

$p(x) = {x}^{2} - (sum)x + product \\ {x}^{2} - 0x - 9 \\ p(x) = {x}^{2} - 9$