Question

A question for all cricket lovers, maths genious in the group !!
How many runs can a single player score in a One day match (50 overs/ 300 balls)
No 'no balls', no wides, no extras, no over throws...So how much runs he can score max???
Apparently this quetion came in IIT and 99% people answered it wrong..
Choices :
A) 1800. B) 1650. C) 1653. D) 1550. E) 1555
F) 1506

Answer 1

Answer: 1653

Step-by-step explanation:

Overs 1 - 49

First five balls = 6*5 = 30

Last ball = 3

Total each over = 33

Total of 1 - 49 overs : 33*49 = 1617

50th over

Six balls all sixes = 36 runs

Total = 1617 + 36 = 1653 runs

Answer 2

Option C - 1653

Given data:

A player should score in a One-day match (50 overs/ 300 balls)  with no 'no balls', no wides, no extras, no overthrows.

To find:

The maximum runs he could score as per the information given.

Solution:

To get the maximum runs under the given condition,

For the first 49 overs, the first five balls of each over should get hit as a six.

The last ball of each over should be a 3 run, in order to get the strike for the next over as in maximum (as there are no overthrows.)

So, for each over in the first 49 overs, we get

For first 5 balls of the over :  5 x 6 = 30

For the last ball of the over: 1 x 3 = 3

Total per over = 30+3 = 33 runs

So, for the first 59 overs, he scores 33 x 49 = 1617 runs

In the last over, as the strike stays with him throughout, he can hit 6 sixes out of the park and finish the match.

So, in the last over i.e., 50th over, he scores 6 x 6 = 36 runs

Total runs he score in the 50 overs = 1617 + 36 = 1653 runs.

Therefore, the maximum number of runs the player can score in a one-day match of 50 overs is 1653 runs (with no 'no balls', no wides, no overthrows, no extras).

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