A question for all cricket lovers, maths genius...
How many runs a single player can score in One day match (50 overs/ 300 balls)
No 'no balls', no wides, no extras, no over throws...So how much runs he can score max???
Choices :
A) 1800.
B) 1650.
C) 1653.
D) 1550.
E) 1555
F) 1506
No Spam
Give correct answer and I will mark you Brainliest!!!
Answers
100..
200..
500..
1000..
1500..
Oh no 1500 crossed let's see how many runs a batsman can score keeping the condition in mind.
First over batsman A is on strike and hits 5 long sixes in 5 consecutive deliveries, and on the last ball flick the ball to the boundary and take three runs. End of the over and score is 6*5+3=33. Team total is 33.
Batsman B is again on non -striking end as A has taken three runs on last delivery of previous over.
Next over the batsman A repeats the same thing and struck maximum 5 sixes and took 3 runs on last delivery. So again total runs in the over is 33 and teams total is 66
After end of 2 over
Batsman A - 66
Batsman B - 0
Total score -66 .
This is repeated till the 49th over .
After 49th over
Batsman A - 1617
Batsman B -0
Total score - 1617.
50th over.
Batsman A is on strike and without wasting any delivery he hits 6 sixes in a over and become overnight star.
Now after the end of 50th over
Batsman A-1617+36=1653
Batsman B-0+0+0…=0
Total score - 1653.
Hard luck for Batsman B didn't get a chance to play a single ball.
Batsman A hits - 251 sixes world record created in one match.
Hence the total runs score by a batsman in ODI cricket with the condition mentioned above is equal to 1653 runs .
Option C - 1653 runs
Given data:
A player should score in a One-day match (50 overs/ 300 balls) with no 'no balls', no wides, no extras, no overthrows.
To find:
The maximum runs he could score as per the information given.
Solution:
To get the maximum runs under the given condition,
For the first 49 overs, the first five balls of each over should get hit as a six.
The last ball of each over should be a 3 run, in order to get the strike for the next over as in maximum (as there are no overthrows.)
So, for each over in the first 49 overs, we get
For first 5 balls of the over : 5 x 6 = 30
For the last ball of the over: 1 x 3 = 3
Total per over = 30+3 = 33 runs
So, for the first 59 overs, he scores 33 x 49 = 1617 runs
In the last over, as the strike stays with him throughout, he can hit 6 sixes out of the park and finish the match.
So, in the last over i.e., 50th over, he scores 6 x 6 = 36 runs
Total runs he score in the 50 overs = 1617 + 36 = 1653 runs.
Therefore, the maximum number of runs the player can score in a one-day match of 50 overs is 1653 runs (with no 'no balls', no wides, no overthrows, no extras).
Learn more:
Three taps A, B and C can fill a tank in 10 minutes, 15 minutes and 20 minutes respectively. If the taps were shut off after 5 minutes, what is the volume of water that overflowed in %?
brainly.in/question/15608672
1 rabbit saw 9 elephants while going to the river. Every elephant saw 3 monkeys going to the river..
brainly.in/question/18196056