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If cot A + cosec A = and A is an acute angle, then the value of cos A is
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Answer:
cot A + cosec A=3
cos A/sin A + 1/sin A =3
(cos A+ 1)/sin A = 3
(cos A+1)/(1-cos^2 A)^.5=3
squaring on both the sides
(cos A+1)^2/(1+cos A)(1- cos A) =9
(cos A+1)/(cos A-1) = 9
(cos A+1) = 9cos A -9
9cos A - cos A = 9+1
8 Cos A = 10
Cos A = 10/8
Cos A = 1.25
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