Question

A Question Here.....!
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A Person standing between the two vertical cliffs produces a sound. Two successive echoes are heard at 4s and 5s. Calculate the distance between the cliffs.(Speed Of Sound in air = 320m/s)
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Answer 1

Answer:

Explanation:

Given

Speed=320

D=?

T=t1+t2

T=4+5=9s

Now

V=2d/t

320=2×d/9

320×9/2=d

160×9=d

1440m=d

Hope it helps you

Answer 2

$\huge{He¥ MaTe!!!}$

☆☞ Here is ur answer ☜☆

✔✔ The distance of first cliff from the person, 2 × D1 = velocity x time D1 = 320 × 4 / 2 = 640 m

✔✔ Distance of the second cliff from the person, D2 = 320 × 5 / 2 = 800 m

✔✔ Distance between cliffs = D1 + D2 = 640 + 800 = 1440 m

HOPE IT HELPS!