Math, asked by maheenbutt1019, 1 year ago

A question paper consists of five problems, each problem having three internal choices. In how many ways can a candidate attempt one or more problems?
A. 63
B. 511
C. 1023
D. 15

Answers

Answered by amitnrw
21

Answer:

1023

Step-by-step explanation:

A question paper consists of five problems, each problem having three internal choices. In how many ways can a candidate attempt one or more problems?

He can attempt Each Question Using any of three Given  options or can choose not to answer That

=> 4 Options for Each Question

Total are 5 Question.

=> 4 * 4 * 4 * 4 * 4

= 1024

But this consist of one case Where he  opted not to answer for Every Question

=>  ways can a candidate attempt one or more problems = 1024 - 1 = 1023

Other Way to solve

He may attempt 5 , 4 , 3 , 2 or 1 Question

Attempted 5 = ⁵C₅ * 3⁵ = 243

Attempted 4 = ⁵C₄ * 3⁴ = 405

Attempted 3 = ⁵C₃ * 3³ = 270

Attempted 2 = ⁵C₂ * 3² = 90

Attempted 1 = ⁵C₁ * 3¹ = 15

Adding all = 243 + 405 + 270 + 90 + 15 = 1023

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