Math, asked by maheenbutt1019, 11 months ago

A question paper consists of five problems, each problem having three internal choices. In how many ways can a candidate attempt one or more problems?
A. 63
B. 511
C. 1023
D. 15

Answers

Answered by jeevani56
0

Answer:

15

Step-by-step explanation:

you can write 15 answer at a time

Answered by jaiswalshivani022
0

Answer:

Step-by-step explanation:Each question can be answered in 4 ways (3 choices + 1 non-attempt). There are five problems.Therefore there are a total of 4^5 ways.

In these 4^5 ways, there is exactly one way in which the student does not attempt any question.

Therefore, required number of ways

= 4^5 - 1 = 1023

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