Question

a question paper contains 6 questions each having alternative. the number of ways an examine can answer oneulf more questions ​

Answer 1

Answer:728

Step-by-step explanation:

For each question he has the choice to either leave the question, do the first alternative or do the second alternative.

Number of choices for each question =3.

Now there are six questions so total combinations = 3*3*3*3*3*3 = 3^6 =729

But the question states that he has to attempt at least one question so this leaves out the case when he doesn't attempt any question.

So no of ways =729-1 =728

Answer 2

Given: A question paper contains 6 questions each having alternative.

Find: The number of ways an examine can answer oneulf more questions.

Solution: The number of ways an examine can answer one or more questions is 728.

While attempting the question paper, the examine has 3 choices. He either answers correctly, answers wrong or leaves the question without attempting it. Since there are 6 questions, the total number of ways of solving the question paper is calculated as shown below.

${3}^{6} = 729$

Now, it is given that the examine must answer one or more questions. This means that atleast one question must be answered. So, leaving an answer unattempted is not a possibility.

$729 - 1 = 728$

Therefore, the number of ways an examine can answer one or more questions is 728.