Question

A Quill tube contains a mercury column of
length 19cm. The length of air column is
24cm when it is held vertically. On
inverting it with its open end downwards
the length of air column will be
(atmospheric pressure = 76cm of Hg)
1) 20cm 2) 30cm 3) 40cm 4) 35cm​

Answer 1

Explanation:

The pressure of air inside while held vertically= 76 + 19 = 95 cm of Hg

Having volume= 24A (A is the area of crossection)

When downside,

pressure=76−19=57

LET height be x

Hence, by having temperature constant,PV= constant, we get

24A∗95=xA∗57

x=40