Question

A quotient obtained or dividing ,(8x^4-2x^2+6x-7) by (2x+1) is(4x^3+px^2-qx+3).Find pq and remainder​

Answer 1

Answer:

The reminder is -10.

Step-by-step explanation:

The division of

(8x

4

−

2x

2

+

6x−

7)

and

(2x+

1)

is shown above:

Therefore, from the division, we get that the quotient is

(

2

1

(8x

3

−4x

2

+6))

that is

(4x

3

−

2x

2

+

3)

and the remainder is

−10.

But it is also given that the quotient is

(4x

3

+

px

2

−

qx+

3)

, thus on comparing the coefficients of both the quotients

(4x

3

−

2x

2

+

3)

and

(4x

3

+

px

2

−

qx+

3)

, we get

p=−2and

q= 0

Hence,

p=

−2

,

q=

0

and the remainder is −10.

MARK AS BRAINLIEST

Answer 2

Answer:

-10

Please mark me as the brainliest and do follow me if you found this helpful