Math, asked by Power143, 7 months ago

A rabbit fell into a hole that was 14 1/2
feet deep. It couldjump 3 feet, but he slid back a foot each time it jumped.How many jumps does it take it to get out of the hole.

Answers

Answered by Swarup1998

118

Given:

To find: The number of jumps required to take itself out of the whole

Solution:

In the 1st jump, it moves 3 feet and slides back 1 feet.

So position = 3 - 1 feet = 2 feet

In the 2nd jump, it moves 3 feet and slides back 1 feet.

So position = 2 + 2 feet = 4 feet

In the 3rd jump, it moves 3 feet and slides back 1 feet.

So position = 4 + 2 feet = 6 feet

In the 4th jump, it moves 3 feet and slides back 1 feet.

So position = 6 + 2 feet = 8 feet

In the 5th jump, it moves 3 feet and slides back 1 feet.

So position = 8 + 2 feet = 10 feet

In the 6th jump, it moves 3 feet and slides back 1 feet.

So position = 10 + 2 feet = 12 feet

In the 7th jump, it moves 3 feet and its position is 12 + 3 feet = 15 feet > 14.5 feet

i.e., in 7th jump, the rabbit will be out of the hole

Answer: In 7 jumps, the rabbit will get out of the hole.

Answered by amitnrw

Given : A rabbit fell into a hole that was 14 1/2 feét deep. It could jump 3 feet, but he slid back a foot each time it jumped

To find : How many jumps does it take it to get out of the hole.

Solution:

no. After Jump After Slide back

1 3 2

2 5 4

3 7 6

4 9 8

5 11 10

6 13 12

7 15 Rabbit is already out hence no slide back

So 7 jumps are required by rabbit to get out of the hole

Learn more:

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rabbit fell into a hole that was 14 1/2 feet deep.

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