Question

a race car accelerate uniformly from 18 metre per second to 46 metre per second in 2 seconds. determine the acceleration of the car and the distance travelled​

Answer 1

Step-by-step explanation:

Thanks for your question !

The both accelerations in first and second case are given as follows - Vi = 18.5 m/s and Vf = 46.1 m/s and time for both accelerations is 2.47 m/

S

Now, a = v/t

= 46.1 18.5/2.47

a = 11.2 m/s^2

dvi xt + 0.5 × axt^2

d = 18.5 m/s x 2.47 +0.5 × (11.2 d = 45.7 m + 34.1 m

m/s^2) x (2.47 s)^2

d = 79.8 m

Therefore, the acceleration of car is 11.2 m/s^2 and distance (travelled) is 79.8

m.