Question

A race car accelerates on a straight road from rest to a speed of 180 kmh^(-1) in 25s. Assuming uniform acceleration of the car throughout, find the distance covered in this time.

Answer 1

$\Large{\underline{\underline{\bf{Solution :}}}}$

We know that,

$\large{\implies{\boxed{\boxed{\sf{v = u + at}}}}}$

Where,

Initial velocity (u) = 0m/s

Final Velocuty (v) = $\cancel{180} \times \frac{5}{\cancel{18}}$ = 50 m/s

Time taken = 25 s

_________________[Put Values]

$\sf{→50 = 0 + a \times 25} \\ \\ \sf{→a = \frac{\cancel{50}}{\cancel{25}}} \\ \\ \sf{→a = 2 \: ms^{-2}}$

$\rule{200}{2}$

Now,

$\large{\implies{\boxed{\boxed{\sf{s = ut + \frac{1}{2} at^2}}}}}$

$\sf{→s = 0(25) + \frac{1}{2} \times 2 \times (25)^2} \\ \\ \sf{→s = \frac{\cancel{2}}{\cancel{2}} \times 625} \\ \\ \sf{→s = 625 \: m}$

$\therefore$ Distance Covered by the car in 25 seconds is 625 m.