A race car accelerates uniformly from 18.2 m/s to 46.6 m/s in 2.4 seconds. Determine the acceleration of the car and the distance traveled.
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Answer: acceleration 14.2 , distance traveled= 84.576
Explanation : (46.6-18.2)/2.4 gives acceleration
=28.4/2 = 14.2
distance traveled in 2.4 sec by applying s= ut + 1/2 at^2
18.2*2.4 + (1/2 * 14.2 * 2.4^20
= 84.576
Answered by
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Answer:Acceleration = 8.8 m s − 2
Distance = 98.7 m
Explanation:I coudn't show the calculation
sorry mate
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