Question

A race car accelerates uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds. Determine the acceleration of the car.

Answer 1

A = ΔV/t

Acceleration = A = (V-u)/t

${<marquee>{ A = (46.1-18.5)/2.47 = 27.6/2.47 = <strong><em><u>11.2 m/s</u></em></strong>}}$

Answer 2

Given :-

• Initial Velocity (u) = 18.5 m/s
• Final Velocity (v) = 46.1 m/s
• Time taken (t) = 2.47 seconds

To Find :-

• Acceleration (a) = ?

Answer :-

• Acceleration of the car is 11.18 m/s²

Explaination :-

By using first equation of motion we get :

→ v = u + at

→ 46.1 = 18.5 + a(2.47)

→ 46.1 - 18.5 = 2.47a

→ 27.6 = 2.47 a

→ a = 27.6 / 2.47

→ a = 11.18 m/s²

Therefore, Acceleration of the car is 11.18 m/s²