Question

A race car accelerates uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds. Determine the acceleration of the car and the distance traveled​

Answer 1

Explanation:

Here, initial velocity is u=18.5m/s and final velocity is v=46.1m/s 

Time taken t=2.47s

If a be the acceleration of the car.

Using v=u+at,

46.1=18.5+a(2.47)

⟹ a=11.17m/s2

If d be the distance traveled by car.

Using formula v2−u2=2ad,

(46.1)2−(18.5)2=2(11.17)d

⟹ d=79.8m

Answer 2

Answer:

final velocity V = 46.1 metre per second

Explanation:

initial velocity u=18.5m/s

time equals to 2.47 second

acceleration = V -u/t

46.1 - 18.5/2.47

=11.17m/s square

distance s =?

s = UT + 1 by 2 at square

18.5 × 2.47 + one by two 11.7 3 × 2.47 square

=79.76m

79.8 (approx)