Question

A race car accelerates uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds.
Determine the acceleration speed of the car and the distance traveled....

Answer 1

Answer: d = 79.8 m; a = 11.2 m/s^2

Given:

vi = 18.5 m/s

vf = 46.1 m/s

t = 2.47 s

To Find:

d = ??

a = ??

Solution

a = (Delta v)/t

a = (46.1 m/s - 18.5 m/s)/(2.47 s)

a = 11.2 m/s^2

d = vi*t + 0.5*a*t^2

d = (18.5 m/s)*(2.47 s)+ 0.5*(11.2 m/s^2)*(2.47 s)^2

d = 45.7 m + 34.1 m

d = 79.8 m

Answer 2

Answer:

Step-by-step explanation:

Hi here is your answer

vi = 18.5 

vf = 46.1 

t = 2.47

d = ??

a = ??

Formula: a = (Delta v)/t

a = (46.1 m/s - 18.5 m/s)/(2.47 s)

a = 11.2 m/s2

d = vi*t + 0.5*a*t2

d = (18.5 m/s)*(2.47 s)+ 0.5*(11.2 m/s2)*(2.47 s)2

d = 79.