A race car accelerates uniformly from 18.5m/s to 46.1m/s in 2.47 seconds. Determine the acceleration of the car and the distance travelled.
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A for Acceleration d for Distance Travelled
Answer: a = 11.2 m/s2m/s and d = 79.8m
Solution: (given): vi = 18.5 vf = 46.1 t = 2.47d = ??a = ??Formula: a = (Delta v)/t
a = (46.1 m/s - 18.5 m/s)/(2.47 s)
a = 11.2 m/s2
d = vi*t + 0.5*a*t2
d = (18.5 m/s)*(2.47 s)+ 0.5*(11.2 m/s2)*(2.47 s)2
d = 45.7 m + 34.1 m
d=79.8
Answer: a = 11.2 m/s2m/s and d = 79.8m
Solution: (given): vi = 18.5 vf = 46.1 t = 2.47d = ??a = ??Formula: a = (Delta v)/t
a = (46.1 m/s - 18.5 m/s)/(2.47 s)
a = 11.2 m/s2
d = vi*t + 0.5*a*t2
d = (18.5 m/s)*(2.47 s)+ 0.5*(11.2 m/s2)*(2.47 s)2
d = 45.7 m + 34.1 m
d=79.8
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