Question

. A race car accelerates uniformly from 21.4 m/sto 46.1 m/sin 2.47 seconds. Determine the

acceleration of the car. (in m/s2

) hii​

Answer 1

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$\color{crimson}{79.78}$

The distance traveled is 79.78 m.

Acceleration is change of velocity over time. The

T = time interval = 2.47 seconds

D= S1 * t + (1/2) * a * t^2

Where:

D: Distance

S1: initial velocity = 18.5 m/s || S2: Final velocity = 46.1 m/s

t: time

a: acceleration

a = (S2-S1)/T = (46.1–18.5)/2.47 = 11.17 m/s^2

D = 18.5*2.47+ (.5) * 11.17 * 2.47^2

D = 45.7 + 34.07 = 79.78m

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