A Race car accelerator uniformly from 18.5m/s to 46.1m/s in 2.47 seconds find the acceleration and distance travelled by the car
Answers
A for Acceleration
d for Distance Travelled
Answer:
a = 11.2 m/s2
m/s and d = 79.8m
Solution:
(given):
vi = 18.5
vf = 46.1
t = 2.47
d = ??
a = ??
Formula: a = (Delta v)/t
a = (46.1 m/s - 18.5 m/s)/(2.47 s)
a = 11.2 m/s2
d = vi*t + 0.5*a*t2
d = (18.5 m/s)*(2.47 s)+ 0.5*(11.2 m/s2)*(2.47 s)2
d = 45.7 m + 34.1 m
d = 79.8 m
(Note: the d can also be calculated using the equation vf2 = vi2 + 2*a*d)
--- Hope it helps you --
Secondary School Math 5+3 pts
A Race car accelerator uniformly from 18.5m/s to 46.1m/s in 2.47 seconds find the acceleration and distance travelled by the car
by Keerthana70 24.10.2018
Report
ANSWER
Answers
keerthana70 is waiting for your help.
Add your answer and earn points.
arnavpandita1
Arnavpandita1Ace
A for Acceleration
d for Distance Travelled
Answer:
a = 11.2 m/s2
m/s and d = 79.8m
Solution:
(given):
vi = 18.5
vf = 46.1
t = 2.47
d = ??
a = ??
Formula: a = (Delta v)/t
a = (46.1 m/s - 18.5 m/s)/(2.47 s)
a = 11.2 m/s2
d = vi*t + 0.5*a*t2
d = (18.5 m/s)*(2.47 s)+ 0.5*(11.2 m/s2)*(2.47 s)2
d = 45.7 m + 34.1 m
d = 79.8 m
(Note: the d can also be calculated using the equation vf2 = vi2 + 2*a*d)