Question

A race car moving on a circular track of radius 20 meters. If car’s speed is 108 km/h, then the magnitude of the centripetal acceleration is​

Answer 1

Explanation:

Centripetal acceleration of the car is 45m / (s ^ 2) .

Explanation :-

We have :-

Radius of the circular track = 20 m

Speed of the car = 108 km/h

Firstly, let's convert the speed of the car from km/h

to m/s.

Rightarrow 1km / h = 5/18 * m / s

108km / h = 108(5/18)

Rightarrow 30m / s

Now we know that when a body is moving around a circular path, it's acceleration is given by :-

a_{c} = v ^ 2 / r

Where :-

⚫a, is acceleration of the body.

⚫vis speed of the body.

⚫r is radius of the circular path.

Rightarrow a_{c} = (30) ^ 2 / 20

a_{c} = 900/20

→ a_{r} = 45m / (s ^ 2)

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