Question

a race car starting from rest accelerates at a constant rate of 5m/s2 for some time after which it deacelerates with 10m/s2 and comes to rest if total time required is 9 sec then maximum speed aquired by the car is

Answer 1

Answer:

30

Explanation:

V max =(a×b×T)/(a+b) where a=acceleration,b=deceleration,T=total time

so Vmax =(5×10×9)/(5+10)

=450/15

=30