Question

A race car traveling on a straight part of a track has an initial velocity of 10.0 m/s. If the car then accelerates at 2.00 m/s2, how far will the car travel in 3.0 seconds?​

Answer 1

Correct Question :⠀⠀⠀

›»› A race car traveling on a straight part of a track has an initial velocity of 10.0 m/s. If the car then accelerates at 2.00 m/s², how far will the car travel in 3.0 seconds?

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Answer :

›»› The Distance travelled by a race car = 39 m

Given :

• Initial velocity of a race car = 10.0 m/s
• Acceleration of a race car = 2.00 m/s²
• Time taken by a car = 3.0 sec

To Find :

• Distance travelled by a race car = ?

Required Solution :

Before we star our solution, let's first know about Distance$.$

✒ Distance :

• Distance is a scalar quantity.
• The SI unit of Distance is meter.
• The CGS unit of Distance is cm.
• Distance in represented by s.

So let's start our solution...

In the above question, we are provided that Initial velocity is 10.0 m/s so, we can write 10 m/s, Acceleration is 2.00 m/s² so, we can write 2 m/s², Time taken is 3.0 sec so we can write 3 sec. Because zero has no value after the point.

Now, we have Initial velocity, Acceleration, and time taken by race car,

• Initial velocity of a race car = 10 m/s
• Acceleration of a race car = 2 m/s²
• Time taken by a race car = 3 sec

And we need to find Distance travelled by race car.

We can find Distance travelled by a race car by using the second equation of motion which says s = ut + ½ at².

Here,

• s is the distance in m.
• u is the Initial velocity in m/s.
• t is the Time taken in second.
• a is the Acceleration in m/s².

So let's find Distance travelled (s) !

From second equation of motion

⇛ s = ut + ½ at²

⇛ s = 10 × 3 + ½ × 2 × 3²

⇛ s = 10 × 3 + ½ × 2 × 9

⇛ s = 30 + ½ × 2 × 9

⇛ s = 30 + 1 × 9

⇛ s = 30 + 9

⇛ s = 39 m

║Hence, the distance travelled by a race car is 30 m.║