Question

a race scooter is seen accelerating uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds. determine the acceleration of the scooter and the distance travelled. i will make brainlest

Answer 1

Answer:

given initial velocity u=18.5m/s

finial velocity v=46.1m/s...

t=2.47 s

use newtons ist eqn of motion

v=u+a*t

a*t=v-u

a=v-u/(t)

put the values of v u t in above eqn

a=46.1-18.5/(2.47)

a=27.6/(2.47)

a=11.174 m/s(ans)

now use 2nd eqn of motion and determine the distance travelled is as shown below

s=u*t+(1/2)a*t^2

s=18.5*2.47+((.5)*11.174*2.47^2)

s=78.781 m

therefore aceeleration a=11.174 m/s

and distance travelled is S=78.781 m

Answer 2

Answer:

ᴀ=11.174ᴍ/ꜱ

ꜱ=78.781ᴍ