Question

a race scoter is seen acelerating uniformly from 18.5m/s to 46.1m/s in 2.47 sec . determine the acceleration of the scooter and the distance traveled.

Answer 1

hi,

A for Acceleration

d for Distance Travelled

Answer:

a = 11.2 m/s2

m/s and d = 79.8m

Solution:

(given):

vi = 18.5 

vf = 46.1 

t = 2.47

d = ??

a = ??

Formula: a = (Delta v)/t

a = (46.1 m/s - 18.5 m/s)/(2.47 s)

a = 11.2 m/s2

d = vi*t + 0.5*a*t2

d = (18.5 m/s)*(2.47 s)+ 0.5*(11.2 m/s2)*(2.47 s)2

d = 45.7 m + 34.1 m

d = 79.8 m

(Note: the d can also be calculated using the equation vf2 = vi2 + 2*a*d)

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