Math, asked by RohitRudra1, 1 year ago

a race track in the form of ring whose inner circumference is 264 m and the outer circumference is 308 find the width of the track


RichaP: Let radius of outer circle be R and inner circle be r.
Circumference of outer circle of race track = 308m
2πR=308
R=(308*7)/(22*2)
R=2156/44
R=49m

Circumference of inner circle of race track=264m
2πr=264
r=(264*7)/(22*2)
r=1848/44
r=42m

Answers

Answered by RichaP
37
Let radius of outer circle be R and inner circle be r.
Circumference of outer circle of race track = 308m
2πR=308
R=(308*7)/(22*2)
R=2156/44
R=49m

Circumference of inner circle of race track=264m
2πr=264
r=(264*7)/(22*2)
r=1848/44
r=42m

Width of race track=Radius of outer circle - Radius of inner circle
Width of race track=49-42=7m

Width of race track is 7m.

Answered by RashiBajaj
4

Hey mate here is your answer.

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