a race track in the form of ring whose inner circumference is 264 m and the outer circumference is 308 find the width of the track
Answers
Answered by
37
Let radius of outer circle be R and inner circle be r.
Circumference of outer circle of race track = 308m
2πR=308
R=(308*7)/(22*2)
R=2156/44
R=49m
Circumference of inner circle of race track=264m
2πr=264
r=(264*7)/(22*2)
r=1848/44
r=42m
Width of race track=Radius of outer circle - Radius of inner circle
Width of race track=49-42=7m
Width of race track is 7m.
Circumference of outer circle of race track = 308m
2πR=308
R=(308*7)/(22*2)
R=2156/44
R=49m
Circumference of inner circle of race track=264m
2πr=264
r=(264*7)/(22*2)
r=1848/44
r=42m
Width of race track=Radius of outer circle - Radius of inner circle
Width of race track=49-42=7m
Width of race track is 7m.
Answered by
4
Hey mate here is your answer.
Attachments:
Similar questions
English,
8 months ago
Political Science,
8 months ago
Social Sciences,
1 year ago
English,
1 year ago
Chemistry,
1 year ago
Circumference of outer circle of race track = 308m
2πR=308
R=(308*7)/(22*2)
R=2156/44
R=49m
Circumference of inner circle of race track=264m
2πr=264
r=(264*7)/(22*2)
r=1848/44
r=42m