Question

A race track is formed by two concentric Circles cohose inner circumference is 528 m and outer circumference is 616 m, find width of track.​

Answer 1

Answer:

14 m

Step by Step explanation:

Let the radius of inner track =r

2πr=528m

$2 \times \frac{22}{7} \times r = 528m$

r=84

let the radius of outer track =R

2πR=396

$2 \times \frac{22}{7} \times r = 616$

R=98

width of track= radius of outer track−radius of inner track

width of track= radius of outer track−radius of inner track=98−84=14m.

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