Question

a race track is in the form of a ring the inner circumference of which is 625m and the outer circumference is 757m find the width of the track​

Answer 1

inner ring circumference 625m

outer ring circumference 757m

$inner \: ring \: 2\pi r = 625 \\ r = \frac{625 \times 7}{22 \times 2} \\ r = 99.4m \\ outer \: ring \: 2\pi r = 757 \\ r = \frac{757 \times 7}{22 \times 2} \\ r = 120.4 \\ width \: of \: ring \: = radius \: of \: outer \: circle - radius \: of \: inner \: circle \\ width \: = 120.4 - 99.4 \\ = 21m$

Answer 2

Answer:

here u goo my friend have a nice night