Question

A race track is in the form of a ring whose inner circumference is 528 m and the outer circumference is 616 m. Find the width ​

Answer 1

Step-by-step explanation:

Outer Circumference = 616 m

So,

2 x pi x r = 616

44/7 x r = 616

r = 616 x 7/44

r = 98

Radius = 98 m

Inner Circumference = 528 m

So,

2 x pi x r = 528

44/7 x r = 528

r = 528 x 7/44

r = 84

Radius = 84 m

So, width of the path = (98 - 84)m

= 14m