Question

A race track is in the form of a ring whose inner circumference is 440m and the width of the track is 7m .Find the area of the track.

Answer 1

Answer:

Step-by-step explanation:

circumference  of the inner track = 4

radius = ?

circumference = 2$\pi$r

$2*\frac{22}{7} *r \\440/2=\frac{22}{7} *r\\220*\frac{7}-{22} = r \\70=r$

area of the track = ?

radius = 7m + 70 m= 77 m

area = $\pi r^{2}$

= 22/7*77m *77m

= 22*11*77

=18634 meter square

Answer 2

Answer:3234 m sq.

Inner circumference = 440m

Radius of it = x

2×22 × x = 440m

7

44x = 440m

7

x = 440 × 7

44

x = 70m

Area of inner ring =. 22×70×70

7

= 15400m sq.

Width of track = 7m

Radius of outer ring = 70m + 7m

= 77m

Outer ring. Area = 22×77×77

7

= 18634m sq.

Area of track = Area of outer ring - area of inner ring

= 18634m sq. - 15400m sq.

= 3234m sq.

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