Question

A race track is in the form of a ring whose inner circumference is 352 m and the outer circumference is 396 m. Find the width of the track. ​

Answer 1

Given :

• A race track is in the form of a ring whose inner circumference is 352 m.
• The outer circumference is 396 m.

To find :

• The width of the track =?

Formula Used :

• Circumference of circle = 2πr

Step-by-step explanation :

Let the outer and inner radii of the ring be R metres and r metres respectively.

Outer Circumference, = 2πR = 396 m.

Inner Circumference = 2πr = 352 m.

2 × (22/7) × R = 396 m

R = 396 × 7/22 × 1/2 = 63 m.

And, 2 × (22/7) × r = 353 m

r = 352 × 7/22 × 1/2 = 56 m.

So, Width of the track = (R - r) m

Substituting the values, we get,

= 63 - 56

= 7.

Therefore, Width of the track = 7 m.

Answer 2

Answer:

The width of the track :

Given:

➛ The inner circumference of race track is

352m.

➛The outer circumference of race track is

369 m.

To Find:

The width of the track.

Solution:

Let the inner and outer radii of the track be r meters and R meters respectively.

We are given,

➛ The inner circumference of race track is

352m.

➛The outer circumference of race track is

369 m.

We know ,

Circumference of circle = 2πr

Then,

According to First condition,

Inner circumference of ring = 352m.

⛬ 2πr = 352

➡ πr = 352 / 2

➡ r = 176 / 3.14

➡ r = 56.05 m

Outer circumference of ring = 396 m.

⛬ 2πR = 396

➡πR = 396 / 2

➡ πR = 198

➡ R = 198 / 3.14

➡ R = 63.05 m

Now,

Width of race track = Difference between raddi

(R - r) = ( 56.05 - 63.05 ) = 7 m

Hence, the width of the track is 7 m.