Question

A race track is in the form of a ring whose inner circumference is 220 m and outer circumference is 308 m. find the width of the track.

Answer 1

here the difference between the circumferrnces =308-220m = 88m
then
$2\pi \times x = 88$
x= 14 m
so the width of the track =14m

Answer 2

Answer:

14 m

Step-by-step explanation:

Solution:

Let r₁ and r₂ be the outer and inner radii of ring.

Then 2πr₁ = 308

2 × 22/7 r₁ = 308

⇒ r₁ = (308 × 7)/(2 × 22)

⇒ r₁ = 49 m

2πr₂ = 220

⇒ 2 × 22/7 × r₂ = 220

⇒ r₂ = (220 × 7)/(2 × 22)  

⇒ r₂ = 35 m  

Therefore, width of the track = (49 - 35) m = 14 m