A race track is in the form of a ring whose inner circumference is 352m nd outer circumference is 396m. find the width of the track
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Answered by
6
352=2x3.14xr
inner r=56.05
396=2x3.14xr
outer r =63.06
width=outer radius - inner radius
=63.06-56.05
=7.01m
inner r=56.05
396=2x3.14xr
outer r =63.06
width=outer radius - inner radius
=63.06-56.05
=7.01m
Answered by
0
inner radius,2πr=352
or,r=56m and outer radius ,r=63m.
inner area=πr^2 =9856sq.cm and outer area=πr^2=12474sq.m
width of the path =12474-9856=2618sq.m
or,r=56m and outer radius ,r=63m.
inner area=πr^2 =9856sq.cm and outer area=πr^2=12474sq.m
width of the path =12474-9856=2618sq.m
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