Question

A race track is in the form of a ring whose inner circumference is of 396 m and
outer circumference is of 440 m. Find the width and area of the track​

Answer 1

Outer circumference = 440m

2πR¹ = 440

${r}^{1} = \frac{440}{2\pi}$

R¹ = 70

Inner circumference = 396cm

2πR² = 396

${r}^{2} = \frac{369}{2\pi}$

R² = 63

Width of track = R¹ - R²

= 70 - 63

= 7m

Area = π(R¹~ - R²~)

= π(70 - 63)

= 931 πm

Hope it helps! ♡