Question

a race track is in the form of a ring whose inner circumference is 220m and outer circumference is 440 m.find the width of the track ​

Answer 1

Given:-

Inner circumference = 220m.

Outer circumference = 440m.

To Find:-

width of the track =?

Solution :-

Let the radius of the outer circle be r1,inner circle be r2.

Outer circumference = 506m

$\sf \implies2 \times \frac{22}{7} \times r1 = 506m \\ \\ \sf \implies r1 = 80.5m$

Inner circumference = 440 m

$\sf \implies2 \times \frac{22}{7} \times r2 = 440m \\ \\ \sf \implies r2 = 70m$

Hence,width of the track = 80.5 - 70 = 10.5m

Answer 2

Step-by-step explanation:

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