Math, asked by jayakhachane, 2 months ago

A race track is in the form of a ring whose inner circumference is 220m and

the outer circumference is 308m. Find the width of the track.​

Answers

Answered by Anonymous
0

Answer:

Width = r2 - r1

» Width = (308 - 220)/2π

» Width = 88/2π

» Width = 14 m

Answered by ButterflyUSR
3

Answer:

Let r₁ and r₂ be the outer and inner radii of ring.

Then 2πr₁ = 308

2 × 22/7 r₁ = 308

⇒ r₁ = (308 × 7)/(2 × 22)

⇒ r₁ = 49 m

2πr₂ = 220

⇒ 2 × 22/7 × r₂ = 220

⇒ r₂ = (220 × 7)/(2 × 22)

⇒ r₂ = 35 m  

Therefore, width of the track = (49 - 35) m = 14 m

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