Question

A race track is in the form of a ring whose inner circumference is 352 m, and the outer circumference is 396 m. Find the width of the track.

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Answer 1

Answer:

Step-by-step explanation:

Let the radius of inner track =r

2πr=352

2×  7 /22

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×r=352

r=56

let the radius of outer track =R

2πR=396 2×  7 /22  ×R=396

R=63

width of track= radius of outer track−radius of inner track

=63−56=7m.

Answer 2

Let the outer and inner radii of the ring be R metres and r metres respectively. Then,

2πR = 398 and 2πr = 352

→ 2×22/7×R = 396 and 2×22/7×r = 352

→ R = 396=7/22×1/2 and r = 352×7/22×1/2

→ R = 63 m and r = 56 m.

Hence, width of the track = (R – r) metres = (63 – 56) metres = 7 metres.