Math, asked by 180337kumaran, 18 days ago

A race track is in the form of a ring whose inner circumference is 352m, and the outer circumference is 396m. Find the width of the track.​

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Answers

Answered by ranidevi63757
3

Answer:

hope this answer will be helpful.

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Answered by Syamkumarr
1

Answer:

The width of the track is 7m.

Step-by-step explanation:

Given, the inner circumference = 352m

and the outer circumference = 396m

Let the radius of the inner ring be 'r' and that of the outer ring be 'R'

We know that circumference of a circle = 2πr

where r is the radius of the circle.

Therefore, using the same formula for the inner ring, we get

2πr = 352

=>  πr = 176

=> \frac{22}{7} r = 176

=> r = 176 * \frac{7}{22}

=> r = 56

Therefore, the inner radius is 56m.

Now,  using the same formula for the outer ring, we get

2πR = 396

=>  πR = 198

=> \frac{22}{7} r = 198

=> r = 198 * \frac{7}{22}

=> r = 63

Therefore, the outer radius is 63m.

We need to find the width of the track,

Width = Outer radius - Inner radius

          = 63 - 56

          = 7m

Therefore, the width of the track is 7m.

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