Question

A race track is in the form of a ring whose inner circumference is 220m and outer circumference is 440 m.find the width of the track

Answer 1

so the first circumference

$220= 2× \frac{22}{7} × r$

$10= \frac{2}{7} × r$

$\frac{10×7}{2} = r$

$r = 35$

and the outer circumference

$440 = 2× \frac{22}{7} × r$

$40 = \frac{2}{7} × r$

$\frac{40×7}{2} = r$

$r = 140$

so the width would be
$R_2 - R_1$

$140-35$

$= 105$

so width is 105