Question

A race track is in the form of a ring whose inner circumference is 352 m, and the outer circumference is 396 m. Find the width of the track

Answer 1

let the radius of inner track = r
2 pie r = 352
r = 56
let the radius of outer track = R
2 pie R = 396
R = 63
width of track = radius of outer track - radius of inner track
=63 - 56
= 7 m

Answer 2

Answer:

The width of the track is 7 m

Step-by-step explanation:

Let the radius of the inner ring be r and the radius of the outer ring be R.

Given that circumference of inner circle = 352 m and circumference of outer circle = 395 m

We know that the general formula for calculating the circumference of circle is,

Circumference of inner ring = $2 \pi r$

$352=2 \times \frac{22}{7} \times r$

$r=\frac{352}{2} \times \frac{7}{22}$

$r=56 \ m$

And, Circumference of outer ring = $2 \pi R$

$\begin{array}{l}{396=2 \times \frac{22}{7} \times R} \\ {R=\frac{396}{2} \times \frac{7}{22}} \\ {R=63 \ \mathrm{m}}\end{array}$

Thus, the width of the track = 63 m – 56 m = 7 m