Question

A race track is in the form of a ring whose inner and outer circumferences are 437 m and 503 m

respectively. Find the width of the track and also its area

Answer 1

area of track=area of outer track-area of inner track
437-503=66 area of track

Answer 2

Let rm and Rm be the radii of inner and outer boundaries.

Then, 2πr=437 and R=5032π

Width of the track =(R−r)m

(5032p−4372π)m

=12π×(503437)m

=(12×722×66)m=10.5m

Area of the track =π(R2−r2)m2=π(R+r)(R−r)m2

=[π5032π=4372π×10.4]m2

[∴(r−r)=10.5]

=[(π×9402π)×10.5]m2(470×212)m2

=(235×21)m2=4935m2