Question

A race track is in the form of a ring whose outer circumference is 660 m and inner circumference is 616 metre find the width of the race track.(take
$take \pi = \frac{22}{7}$
​

Answer 1

Answer:

44

Step-by-step explanation:

π×rsquare = 660

660- 616=44

Answer 2

Step-by-step explanation:

1. circumference of outer ring = 2 pi r

• 660 m = 2× 22/7×r
• (660/44)×7 = r
• r=105

2. circumference of inner circle = 616 m

• 2 pi r = 616
• 2×22/7×r = 616
• r = (616×7)/44
• r=98

3. width of race track = 105 -98 = 7 m