A race track is in the form of ring whose inner circumference is 220m and outer circumference is 550m find the width of the track
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let the inner radius = r
the outer radius =R
according to question
2× pi × r = 220
r= 35 m
2×pi× R = 550
R= 87.5
therefore width of track = R-r
= 87.5 - 35
= 52.5 m
the outer radius =R
according to question
2× pi × r = 220
r= 35 m
2×pi× R = 550
R= 87.5
therefore width of track = R-r
= 87.5 - 35
= 52.5 m
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