Question

a racetrack is in the form of a ring whose inner circumference is 352 and the outer circumference is 396 M find the width of the track

Answer 1

no circumference of inner circle = 352 m

or, 2πr = 352 m
2×22/7×r = 352 m
r = 352×7/22×2
r = 56 m
Now,
circumference of outer circle = 396 m

or, 2πr = 396m
2×22/7×r = 396m
r = 396×7/22×2
= 63 m
width of track = radius of outer circle - radius of
inner circle
= 63m - 56m
= 7m

Answer 2

circumference of samller circle =2πr
352 =2*22/7*r
r1=56

cirumference of bigger circle =2πr
396=2πr
r2=63

Width of track= r2-r1
=63-56
=7