a racing bike has uniform acceleration 4ms-1 then distances will it cover in 5s after the starting from rest is
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Answer:distance traveled in 5sec=50m.
Explanation:using,s=ut+1/2at^2s. ( # this formula is only used uniformly accelerated motion.)
=(0)5+1/2*4*(5)^2.
s=0+2*25s.
=2*25=50m.
s=distance travelled,
u=initial velocity,
a= accelration,
t= time taken.
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