Question

A racing car accelerates uniformly from 18.5km/hr to 46.1km/hr in 2.47 seconds. Determine the acceleration of the car and the distance travelled

Answer 1

Answer:

Explanation:

Initial Velocity (u) = 18.5 km/hr

= [18.5*5/18] m/s

= 5.13 m/s

Final Velocity (v) = 46.1 km/hr

= [46.1*5]/18 m/s

= 12.80 m/s

Time (t) = 2.47 s

Acceleration (a) = (v-u)/t

= (12.80-4.13)/2.47  m/s²

= 8.67/2.47  m/s²

= 3.51 m/s²

Let the Distance travelled be denoted as 'S'.

According to the formula,

= v² = u²+2aS

= (12.80)² = (5.13)² + 2[3.51S]

= 163.84 = 26.31 + 7.02S

= 137.53 = 7.02S

= 19.59 m = S

Hope this helps.