Question

A racing car has a uniform acceleration of 2ms^2, what distance will it cover in 5s after start

Answer 1

Answer:

25 metres

Explanation:

Given :

• Initial velocity = u = 0 m/s

• Time taken = t = 5 seconds

• Acceleration of the racing car = a = 2 m/s²

To find :

• Distance travelled by the racing car

Using the second equation of motion :

S=ut+½×at²

S=0×5+½×2×5²

S=0+5²

S=0+25

S=25 metres

The distance covered by the racing car is equal to 25 metres

More :

First equation of motion = v=u+at

Third equation of motion = v²-u²=2as

Answer 2

GiveN :

• Acceleration (a) = 2 m/s²
• Initial velocity (u) = 0 m/s
• Time interval (t) = 5 s

To FinD :

• Distance travelled by car

SolutioN :

Use 1st equation of motion for calculating value of final velocity :

⇒v = u + at

⇒v = 0 + 2 * 5

⇒v = 0 + 10

⇒v = 10

∴ Final velocity of car is 10 m/s

________________________

Now, use 3rd equation of motion for calculating distance travelled by car.

⇒v² - u² = 2as

⇒10² - 0² = 2 * 2 * s

⇒100 - 0 = 4s

⇒100 = 4s

⇒s = 100/4

⇒s = 25

∴ Distance travelled by car after 5s after start is 25 m.