A racing car has a uniform acceleration of 4 m S ^2 what distance will it cover on 10 sec
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it will cover 200m as inital it is at rest so......
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ANSWER:-
Known Terms:-
u = Initial Velocity
a = Acceleration
t = Time
s = Distance
Given:-
Initial Velocity of car, u = 0 ms-1
Acceleration of car, a = 4 m s-2
Time taken by the car, t = 10 s
To Find:-
Distance (s)
Solution:-
Here we have to find the distance
so,
Here, we use 3rd equation of motion that is s = ut + at²
⇒ s = ut + at²
⇒ s = 0 + () × 4 × 10²
⇒ s = 0 + () × 4 × 10 × 10
⇒ s = () × 400 m
⇒ s = 200 m
The distance cover in 10 s after start is 200 m.
THANKS!!!
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