Question

A Racing car has a uniform acceleration of 4 m /s*2.What distance will it cover in 10s after start?

Answer 1

→Acceleration, a = 4 m/s²

→Time, t = 10 s

→Initial velocity, u = 0 m/s

(As the vehicle is at rest before it starts)

We know,

$\boxed{\sf{\star\ v=u+at}}$

Putting the values :-

$\sf{\implies v=0+4(10)}\\\\\sf{\implies v=0+40}\\\\\sf{\implies v=40\ m/s}$

$\rule{100}1$

We also know that,

$\boxed{\sf{\star\ v^2=u^2+2as}}$

Putting the values :-

$\sf{\implies (40)^2=(0)^2+2\times 4 \times s}\\\\\sf{\implies 1600=0+8s}\\\\\sf{\implies 8s=1600}\\\\\sf{\implies s=\dfrac{1600}{8} }\\\\\boxed{\boxed{\sf{\implies s=200\ m}}}$

Hence, the racing car covers a distance id 200 m.

Answer 2

Aɴsᴡᴇʀ:

• Distance covered by the racing car = 200 metre

Gɪᴠᴇɴ:

• Initial velocity = 0
• Acceleration = 4m/s²
• Time = 10 Seconds

Nᴇᴇᴅ Tᴏ Fɪɴᴅ:

• Required distance covered = ?

Solution:

Bʏ ᴛʜᴇ sᴇᴄᴏɴᴅ ᴇǫᴜᴀᴛɪᴏɴ ᴏғ ᴍᴏᴛɪᴏɴ:

• s = ut + 1/2 at²

Pᴜᴛᴛɪɴɢ ᴛʜᴇ ᴠᴀʟᴜᴇs:

➜ s = 0 × 10 + (1/2) × 4 × 10²

➜ s = 0 + (1/2) × 4 × 10 × 10

➜ s = (1/2) × 400

➜ s = 200 metre

Tʜᴇʀᴇғᴏʀᴇ:

• Distance covered by the racing car = 200 metre

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